r = 1s = log(1/r) = 0.00N(r) = 1Φ = log N = 0.00Φ/s = —
The boxes above are the ones that meet the set. Each time the width shrinks by a
factor of 3, the number of survivors doubles — and the point below climbs one notch along a
line whose slope is log 2 / log 3.